x/(x-1)+1/(x+1)=(x^2+1)/(x^2-1)

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Solution for x/(x-1)+1/(x+1)=(x^2+1)/(x^2-1) equation:


D( x )

x^2-1 = 0

x+1 = 0

x-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-1) U (-1:1) U (1:+oo)

x/(x-1)+1/(x+1) = (x^2+1)/(x^2-1) // - (x^2+1)/(x^2-1)

x/(x-1)+1/(x+1)-((x^2+1)/(x^2-1)) = 0

x/(x-1)+1/(x+1)+(-1*(x^2+1))/(x^2-1) = 0

(x*(x+1)*(x^2-1))/((x-1)*(x+1)*(x^2-1))+(1*(x-1)*(x^2-1))/((x-1)*(x+1)*(x^2-1))+(-1*(x^2+1)*(x-1)*(x+1))/((x-1)*(x+1)*(x^2-1)) = 0

x*(x+1)*(x^2-1)+1*(x-1)*(x^2-1)-1*(x^2+1)*(x-1)*(x+1) = 0

x^4-x^4+2*x^3-2*x^2-2*x+1+1 = 0

2*x^3-2*x^2-2*x+2 = 0

2*x^3-2*x^2-2*x+2 = 0

2*(x^3-x^2-x+1) = 0

x^3-x^2-x+1 = 0

{ 1, -1 }

1

x = 1

x^3-x^2-x+1 = 0

1

x-1

x^2-1

x^3-x^2-x+1

x-1

x^2-x^3

1-x

x-1

0

x^2-1 = 0

DELTA = 0^2-(-1*1*4)

DELTA = 4

DELTA > 0

x = (4^(1/2)+0)/(1*2) or x = (0-4^(1/2))/(1*2)

x = 1 or x = -1

x in { -1, 1, 1}

2*(x+1)*(x-1)^2 = 0

(2*(x+1)*(x-1)^2)/((x-1)*(x+1)*(x^2-1)) = 0

(2*(x+1)*(x-1)^2)/((x-1)*(x+1)*(x^2-1)) = 0 // * (x-1)*(x+1)*(x^2-1)

2*(x+1)*(x-1)^2 = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-1 )

x-1 = 0 // + 1

x = 1

x in { -1}

x in { 1}

x belongs to the empty set

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